// arabc1.cpp

// array of pointers to arrays
// superficially similar to 2-D array, but not the same

#include <iostream>
#include <iomanip>

using namespace std;

int main()
{

  // some arrays of ints
  // dummy vbls to keep arrays from being contiguous

  int a[] = {1, 2, 3};
  int j1;

  int b[] = {10, 20, 30};
  int j2;
  int j3;

  int c[] = {100, 200, 300};
  int j4;
  int j5;
  int j6;

  // an array of pointers to the arrays above

  int *ar[] = {a, b, c};

  cout << " a     = " << a << endl;
  cout << " b     = " << b << endl;
  cout << " c     = " << c << endl;
  cout << endl;

  cout << " b[1]     = " << b[1] << endl;
  cout << " b+1      = " << b+1 << endl;
  cout << " (b+1)[1] = " << (b+1)[1] << endl;
  cout << endl;

  cout << " 1[b]     = " << 1[b] << endl;
  cout << endl;

  cout << " ar    = " << ar << endl;
  cout << " ar[1] = " << ar[1] << endl;
  cout << endl;

  cout << " *ar[1] =   " << *ar[1]   << endl;
  cout << " *(ar[1]) = " << *(ar[1]) << endl;
  cout << " (*ar)[1] = " << (*ar)[1] << endl;
  cout << endl;

  // accessing the inner arrays indirectly through the outer array

  cout << "ar[1][1] = " << ar[1][1] << endl;
  cout << endl;

  // Order of operations:
  // .   member
  // ->  member indirect through pointer
  // []  subscript
  // *   dereference

  cout << "ar =         " << ar << endl;
  cout << "ar+1 =       " << ar+1 << endl;
  cout << "(ar+1)[1] =  " << (ar+1)[1] << endl;
  cout << "*(ar+1)      " << *(ar+1) << endl;
  cout << endl;

  cout << "*((ar+1)[1])  = " << *((ar+1)[1]) << endl;
  cout << "(*(ar+1))[1]  = " << (*(ar+1))[1] << endl;
  cout << "*(ar+1)[1]    = " << *(ar+1)[1] << endl;

  return 0; 
} 

/* Sample output:

 a     = 0xffbefc10
 b     = 0xffbefbf8
 c     = 0xffbefbe0

 b[1]     = 20
 b+1      = 0xffbefbfc
 (b+1)[1] = 30

 1[b]     = 20

 ar    = 0xffbefbc0
 ar[1] = 0xffbefbf8

 *ar[1] =   10
 *(ar[1]) = 10
 (*ar)[1] = 2

ar[1][1] = 20

ar =         0xffbefbc0
ar+1 =       0xffbefbc4
(ar+1)[1] =  0xffbefbe0
*(ar+1)      0xffbefbf8

*((ar+1)[1])  = 100
(*(ar+1))[1]  = 20
*(ar+1)[1]    = 100

*/